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mark!

[dead poets society]

TYPE OF QUESTION:
physics :c

YOUR QUESTION:
Oxygen atoms have 8 protons in their nuclei.
What is the total charge of an oxygen nucleus?

and

If the first electron is located 6.8x10⁻¹¹ m outside of the nucleus, then calculate the electric force between the nucleus and the first electron.

if someone could please help me and explain these to me, that would be very much appreciated. i really struggle with physics and need some help. ^^

[saka.]

TYPE OF QUESTION: Math
YOUR QUESTION:

Simplify.

x^4 y^7
---------
xy^3

The ^# things are exponents and the line between the two numbers is a fraction/division sign. I've spent 20 minutes trying to figure this one out but it just keeps coming out to the same answer that is wrong. Help?

[hikaru-i]

TYPE OF QUESTION: Math
YOUR QUESTION:

Simplify.

x^4 y^7
---------
xy^3

The ^# things are exponents and the line between the two numbers is a fraction/division sign. I've spent 20 minutes trying to figure this one out but it just keeps coming out to the same answer that is wrong. Help?

I suck at math but this I can help you with
so when you divide variables with exponents you subtract the exponents, in this case look at it this way with each exponent
we can do xs first, x^4 - x^1
then ys, y^7 - y^3

so write them out and group the exponents together
x^(4-1) and y^(7-3)
so you get x^3y^4

hope this helps

[Kylee Hart]

TYPE OF QUESTION: Math
YOUR QUESTION:

Simplify.

x^4 y^7
-------
xy^3

The ^# things are exponents and the line between the two numbers is a fraction/division sign. I've spent 20 minutes trying to figure this one out but it just keeps coming out to the same answer that is wrong. Help?

So I'm just gonna write this out to make it a little bit easier to see, with * representing multiplication.

x*x*x*x*y*y*y*y*y*y*y
-------------------------
x*y*y*y

Now we can divide by x/x, because the numerator and denominator both have at least one x

x*x*x*x*y*y*y*y*y*y*y
--------------------------------
x*y*y*y

And now we can divide by y^3/y^3, because the numerator and denominator both have at least y^3.

x*x*x*y*y*y*y*y*y*y
-------------------------------
y*y*y

This gives us x*x*x*y*y*y*y, or x^3y^4

Make sense?

[saka.]

thank you all for the help <3

[storm coming.]

mark

[Munin]

TYPE OF QUESTION: Chemistry
YOUR QUESTION:

H2O2 + H2O -> ???

Context: hydrogen peroxide is added to lake water to help kill algae bloom.
Have to write the chemical equation for it but I'm not sure what it really creates?

I can't seem to find anything on it with Google. I'm not sure if it synthesizes and becomes H4O3(which I can't find anything on either) but I don't know what else it could create?

[aequilibrium]

TYPE OF QUESTION: Chemistry
YOUR QUESTION:

H2O2 + H2O -> ???

Context: hydrogen peroxide is added to lake water to help kill algae bloom.
Have to write the chemical equation for it but I'm not sure what it really creates?

I can't seem to find anything on it with Google. I'm not sure if it synthesizes and becomes H4O3(which I can't find anything on either) but I don't know what else it could create?

It might have something to do with the pH of the water, so it could be something like H2O2 + H2O -> H3O+ + HO2- but I'm not sure (actually far from sure, tbh) so I think you should do some more research on it ^-^
Hope this helped, though!

[Munin]

TYPE OF QUESTION: Chemistry
YOUR QUESTION:

H2O2 + H2O -> ???

Context: hydrogen peroxide is added to lake water to help kill algae bloom.
Have to write the chemical equation for it but I'm not sure what it really creates?

I can't seem to find anything on it with Google. I'm not sure if it synthesizes and becomes H4O3(which I can't find anything on either) but I don't know what else it could create?

It might have something to do with the pH of the water, so it could be something like H2O2 + H2O -> H3O+ + HO2- but I'm not sure (actually far from sure, tbh) so I think you should do some more research on it ^-^
Hope this helped, though!

Yeah I appreciate the help! =D Thank you ^^~ I'll still be searching up stuff but the pH comment definitely helped~ thanks again!