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[Memories]

Does anyone know percentage stuff? Its not really homework but there is this thing i want at a store and it is 50$ and it is going on sale for 75% off anyone know how much it will be?

ok so 75% off is the same as it being a quarter of its original price
so u work out one quarter (25%) of 50
u can work out a quarter by halving twice
so 50 / 2 = 25
and 25 / 2 = 12.5
So it would cost $12.50

Technically the way to figure out percentages is to do this:
Turn the 75% into a decimal by dividing the 75 by 100. So 75% becomes 0.75.
Now just take 0.75 x $50, which equals 37.5, which is the discount.
So subtract the discount from the original price: $50 minus $37.5 equals $12.50.
This will work even when it is not exactly a quarter of its original price.

[Gigglebug]

You can also do percentage like this:

75/100% = X/25%

Then you multiply with 25%

Solve the equation and get the result for X.

With this you can solve any question with percentages.

Basically it's what memories wrote but I find this version easier to convert to other problems.

[swiftheart54]

Does anyone know percentage stuff? Its not really homework but there is this thing i want at a store and it is 50$ and it is going on sale for 75% off anyone know how much it will be?

ok so 75% off is the same as it being a quarter of its original price
so u work out one quarter (25%) of 50
u can work out a quarter by halving twice
so 50 / 2 = 25
and 25 / 2 = 12.5
So it would cost $12.50

Oh i see, thank you c:

Does anyone know percentage stuff? Its not really homework but there is this thing i want at a store and it is 50$ and it is going on sale for 75% off anyone know how much it will be?

ok so 75% off is the same as it being a quarter of its original price
so u work out one quarter (25%) of 50
u can work out a quarter by halving twice
so 50 / 2 = 25
and 25 / 2 = 12.5
So it would cost $12.50

Technically the way to figure out percentages is to do this:
Turn the 75% into a decimal by dividing the 75 by 100. So 75% becomes 0.75.
Now just take 0.75 x $50, which equals 37.5, which is the discount.
So subtract the discount from the original price: $50 minus $37.5 equals $12.50.
This will work even when it is not exactly a quarter of its original price.

Great info thanks!

You can also do percentage like this:

75/100% = X/25%

Then you multiply with 25%

Solve the equation and get the result for X.

With this you can solve any question with percentages.

Basically it's what memories wrote but I find this version easier to convert to other problems.

Thank you as well

[Waki]

Up

[BuddyMaltese]

I HAVE A QUESTION!
TYPE OF QUESTION: Math (Logarithms)
YOUR QUESTION:Solve for x: 3x(10^x) + 10^x = 0

[here's a link to a picture of the question, it's #33, and here's a link to my work(which is wrong but I don't understand why)]
My book says to factor out anything you can, and then solve. I did that and exponentiated the 3 to get 1/3, but the answer in my book is -1/3 ;-;

[wane]

I HAVE A QUESTION!
TYPE OF QUESTION: Math (Logarithms)
YOUR QUESTION:Solve for x: 3x(10^x) + 10^x = 0

[here's a link to a picture of the question, it's #33, and here's a link to my work(which is wrong but I don't understand why)]
My book says to factor out anything you can, and then solve. I did that and exponentiated the 3 to get 1/3, but the answer in my book is -1/3 ;-;

Careful with you x's; sometimes I can't tell if they're an exponent or not (I think that's where you messed up).

Here's a picture of my work:
http://moon-sail.tumblr.com/image/155369813278

1. In the first step, I factored out the 10^x which you've already done.

2. That means, the equation now has two parts, and since you're multiplying them together, either of these parts can equal zero to make the equation true.

The first possibility is 10^x=0, which has no solution because you can't have log of zero (it's an asymptote).

The second possibility is that 3x+1=1 NOT 3^x-1=0. That leads you to 3x=-1 and then x=-1/3

Hopefully that helps; let me know if you need any more clarification. ^^

[BuddyMaltese]

Careful with you x's; sometimes I can't tell if they're an exponent or not (I think that's where you messed up).

Here's a picture of my work:
http://moon-sail.tumblr.com/image/155369813278

1. In the first step, I factored out the 10^x which you've already done.

2. That means, the equation now has two parts, and since you're multiplying them together, either of these parts can equal zero to make the equation true.

The first possibility is 10^x=0, which has no solution because you can't have log of zero (it's an asymptote).

The second possibility is that 3x+1=1 NOT 3^x-1=0. That leads you to 3x=-1 and then x=-1/3

Hopefully that helps; let me know if you need any more clarification. ^^

Oh my gosh, that makes so much more sense cx
Thank you so much, that was driving me crazy!

[Eagle's Eye]

I HAVE A QUESTION!
TYPE OF QUESTION:English
YOUR QUESTION:Can someone give me some tips about what to write in a conclusion? I have this essay due in a few hours but I have no idea how to start on my conclusion. Is there anything you could do except for summarizing and rephrasing your stuff? because I am terrible at these D:

[nickjr]

I HAVE A QUESTION!
TYPE OF QUESTION:English
YOUR QUESTION:Can someone give me some tips about what to write in a conclusion? I have this essay due in a few hours but I have no idea how to start on my conclusion. Is there anything you could do except for summarizing and rephrasing your stuff? because I am terrible at these D:

"All right, I'm nearing the end of your essay. So what's your point? Why are you telling me all of this? What's the point of reading this?"
With those questions in mind (and imagining that someone other than the teacher is going to read the essay, even though it never happens), I usually add one or two non-summary sentences to my conclusion, and these sentences are intended to give the reader something to think about. They often end up being connections to real life or to any earlier course material that I did not mention in the essay.

You may do something similar in your introduction and then have your conclusion be almost like a continuation of your introduction.
Intro: Here's some background about x (maybe draw on outside knowledge)
Body: I'm going to argue something about x
Conclusion: Here's why my argument about x matters

For example:

In a Hamlet essay that I wrote, I argued that Hamlet is a dynamic character.

In my intro, I mentioned how children are usually introduced to "dynamic characters" and briefly compared and contrasted that with what I was about to argue. When I grew up, Hamlet usually wasn't given as an example of a dynamic character. Maybe that has changed. It was actually arguable either way haha one of our essay options was to argue that Hamlet was a dynamic or a static character, and I chose dynamic.

In my conclusion, I referred to my body paragraphs and then my thesis again and gave them as reasons why Hamlet usually wasn't given as an example of a dynamic character, despite being a well-known character who (as I argued) was dynamic. Then I commented on change IRL and how change can be good and bad and I... don't know how to explain what I put in my conclusion without actually typing out the ideas/pasting the words lol but I'd like to think that I answered the question of "okay, you told me that Hamlet is a dynamic character. So what?"

[Eagle's Eye]

@nickjr and lena,
Thank you two so much! C: