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[wingz.]

TYPE OF QUESTION:Oh man more math (sorry for all the math, guys, I just can't remember all the stuff I learned last year.)
YOUR QUESTION: Two different quadratic functions of the form y=9x^2 - kx + 4 each touch the x-axis. Find the two values of k.

Mostly what confuses me about this question is that it seems to be saying that there are only two possible values of k. Can't there be more? I'm also not entirely sure how to go about finding k without being given any other information to work with.

okay so when it talks about quadratics you need to remember the quadratic equation
in this case, to solve for x

x=(-b +/- √(b² - 4ac)) / 2a
sorry that I cant type it clearer

what you do is plug in your values for a, b, and c which are 9, k, and 4 respectively
once you plug in you will get two different answers, one where you add and one where you subtract

I suggest looking here to read more!!
hope that helps <33

[Waki]

^^ wingz, you always get there before I do hehe

[❤ Sunberry ❤]

I'm sure I'll be using this thread a lot, xD -mark-

[Waki]

^^great to see you mark!

[Waki]

Up

[Rabid_Jaguar]

TYPE OF QUESTION: More math ;-; I'm almost finished with it, though!
YOUR QUESTION: Find, in the form y= ax^2 + bx + c, the equation of the quadratic whose graph touches the x-axis at 4 and passes through (2,12).

So I know that I have 2 points (4, 0) and (2, 12). However, without having a third point or having one of these points be a vertex or y-intercept, I don't know how to solve for a, b, and c.

Thanks to anyone who can help and especially to wingz. who has already helped me twice owo

[wingz.]

TYPE OF QUESTION: More math ;-; I'm almost finished with it, though!
YOUR QUESTION: Find, in the form y= ax^2 + bx + c, the equation of the quadratic whose graph touches the x-axis at 4 and passes through (2,12).

So I know that I have 2 points (4, 0) and (2, 12). However, without having a third point or having one of these points be a vertex or y-intercept, I don't know how to solve for a, b, and c.

Thanks to anyone who can help and especially to wingz. who has already helped me twice owo

So I'm in calc rn but I'm just gonna help you with that third point
If you need any more help on this problem feel free to message me I'll be out of class in about a half hour

For the third point, you need a y intercept yes?
Well you can use y = mx + b form
m is the slope, which you find with this formula:
(Y2 - Y1)/(X2-X1) = (12-0)/(2-4) = -6

You plug that and one point in, I used (2, 12)

12 = -6(2) + b
24 = b

So you're y intercept is (0, 24)

Hope that helps!!

[Waki]

^^wow wingz. You lightning speed or something? O.0

[wingz.]

^^wow wingz. You lightning speed or something? O.0

lol math is easy for me
im actually in an engineering specific college calculus class right now
so doing the simple algebra problems is a nice change of pace x'D

[Princess Taozi]

Well I'm DEFINATLY going to use this sometime (I have a feeling that I might need some help later on) Marking <3