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[Waki]

^^zou are correct. In that case, I am wrong. I misread, forgive me ouo

It's alright c: just make sure you read everyone's questions carefully before answering them c: (to avoid future problems)

[wingz.]

TYPE OF QUESTION:math
YOUR QUESTION:the length if Laurie's rectangular swimming pool is triple the width. The pool covers an area of 192m2

A) if Laurie swims across the diagonal and back, how far does she travel? (I know the answer to this a), it should be 151.8 right?)

B) at the same time Laurie starts swimming, her cat walks one lap around the edge of the pool. Laurie can swim 3/4 as fast as her cat can walk. Who will return to the starting point first? Justify your answer. (Now, I got confused here.....I know time=distance over speed, but what's the speed?)

Alright, because there's a lot of confusion, I decided to attempt the problem myself and explain it as clearly as possible.

Since the length of the pool is three times the width, we get the equation L = 3w.

The equation for area is L x w = A, so we substitute in and we get:

3w x w = 192

Now we solve to find w.

3w^2 = 192 (Remember that ^2 is a way of writing "squared.")

w^2 = 64

w = + or - 8 (You may not have gotten into this yet, but basically every positive number has two square roots, since a negative times a negative is always positive. However, it is not possible for something real to have a negative width (how would it work?) so we disregard the negative solution.)

w = 8

Now, to find the length, we substitute back in to that first equation.

L = 3w
L = 3 x 8
L = 24

Now we use the Pythagorean Theorem to find the length of the diagonal. It's important to remember that this theorem only works for right triangles. We know that this one is a right triangle because all angles in a rectangle are right angles.

So, the theorem before substitution is:

a^2 + b^2 = c^2

In the Pythagorean Theorem, c is always the length of the hypotenuse (diagonal). The order of the other two sides doesn't matter.

8^2 + 64^2 = c^2
16 + 4096 = c^2
4112 = c^2
c = 64.1248781675

We would probably want to round this to 64.12 meters.

Then, we simply multiply by 2, since Laurie swims across the diagonal and then back, which equals 128.24 meters.

So, since word problems must be answered with a sentence, we get:

If Laurie swims across the diagonal and back, she will swim 128.24 meters.

As for the second question, I'm a bit of a dummy with speeds and such, but I can tell you that, like Svel said, the cat walks around the perimeter of the pool, so you would use this formula:

L + L + w + w = P

or

2L + 2w = P

aaaaaaaah so so sorry I was working on my own math homework lol
also I had class but thats a different story oops

anywhos, Rabid_Jaguar is correct I went through and checked all the math
ONE BIG THING TO REMEMBER IS YOUR UNITS!!!!!!!!!!!!!!
I cannot stress this enough get into the habit now because later in your math career this will make or break you
I can't even explain how important it is in math and science classes to keep your units, in this case m (meters)
for rounding decimals, this probly doesn't effect any of your rn but its good to keep sf or 2 decimal places

but anyway, can I also say I love the explanation? I do this all on my phone the typing kills me x'D

----------------

for part two, since when you replied to me you seemed confused, is like Rabid_Jaguar said
you can do 2L + 2w = P to find the perimeter

BUT!!!!!! you're looking for which one gets there first not the general perimeter of the problem
the perimeter is only going to effect the cat

Im just going to assume you mean swimming the diagonal back for Laurie in part b

to start off do the above calculation
once you have that number, then you plug into what you have
t (time) = d (distance) / s (speed)

for the cat:

t = d (perimeter #) / x

for Laurie:

t = d (diagonal value = 128.24m ) / (3/4)x

----------------

once you have all youre numbers you can set the equations equal to each other to solve for x
cat = Laurie

once you have the x value plug back in and you can figure out your times!! <33
lemme know if that doesnt make any sense lol but I hope that helps

[Bobkitty246]

TYPE OF QUESTION:math
YOUR QUESTION:the length if Laurie's rectangular swimming pool is triple the width. The pool covers an area of 192m2

A) if Laurie swims across the diagonal and back, how far does she travel? (I know the answer to this a), it should be 151.8 right?)

B) at the same time Laurie starts swimming, her cat walks one lap around the edge of the pool. Laurie can swim 3/4 as fast as her cat can walk. Who will return to the starting point first? Justify your answer. (Now, I got confused here.....I know time=distance over speed, but what's the speed?)

Alright, because there's a lot of confusion, I decided to attempt the problem myself and explain it as clearly as possible.

Since the length of the pool is three times the width, we get the equation L = 3w.

The equation for area is L x w = A, so we substitute in and we get:

3w x w = 192

Now we solve to find w.

3w^2 = 192 (Remember that ^2 is a way of writing "squared.")

w^2 = 64

w = + or - 8 (You may not have gotten into this yet, but basically every positive number has two square roots, since a negative times a negative is always positive. However, it is not possible for something real to have a negative width (how would it work?) so we disregard the negative solution.)

w = 8

Now, to find the length, we substitute back in to that first equation.

L = 3w
L = 3 x 8
L = 24

Now we use the Pythagorean Theorem to find the length of the diagonal. It's important to remember that this theorem only works for right triangles. We know that this one is a right triangle because all angles in a rectangle are right angles.

So, the theorem before substitution is:

a^2 + b^2 = c^2

In the Pythagorean Theorem, c is always the length of the hypotenuse (diagonal). The order of the other two sides doesn't matter.

8^2 + 64^2 = c^2
16 + 4096 = c^2
4112 = c^2
c = 64.1248781675

We would probably want to round this to 64.12 meters.

Then, we simply multiply by 2, since Laurie swims across the diagonal and then back, which equals 128.24 meters.

So, since word problems must be answered with a sentence, we get:

If Laurie swims across the diagonal and back, she will swim 128.24 meters.

As for the second question, I'm a bit of a dummy with speeds and such, but I can tell you that, like Svel said, the cat walks around the perimeter of the pool, so you would use this formula:

L + L + w + w = P

or

2L + 2w = P

Thank-you all for your help! And yea, I realized my mistake ouo yep. But I have a question, shouldn't it be
8^2+24^2=c^2
Rather than
8^2+64^2=c^2?

I mean 64 is the square foot of 8, so yea. C: I could be wrong, and because wingz proved your explanation to be correct, I'm probably wrong, but just want to know why it is 64^2 than 24^2 c:
And @tobias Eaton. It's okie, I know you tried. This is a easy question for the first part, but I made the same mistake as you did ouo.

[wingz.]

Thank-you all for your help! And yea, I realized my mistake ouo yep. But I have a question, shouldn't it be
8^2+24^2=c^2
Rather than
8^2+64^2=c^2?

I mean 64 is the square foot of 8, so yea. C: I could be wrong, and because wingz proved your explanation to be correct, I'm probably wrong, but just want to know why it is 64^2 than 24^2 c:
And @tobias Eaton. It's okie, I know you tried. This is a easy question for the first part, but I made the same mistake as you did ouo.

frickity frack you are correct my friend
I missed that on my tiny screen I am very sorry it should be 24
the work through math is correct just plug in 24 otl

[stranger danger]

Ehh
I hope it's ok to mark. >.<

[Waki]

Feel free to mark! C:

[spooktunes]

markkkkkk

[stranger danger]

c:

[Rabid_Jaguar]

Thank-you all for your help! And yea, I realized my mistake ouo yep. But I have a question, shouldn't it be
8^2+24^2=c^2
Rather than
8^2+64^2=c^2?

I mean 64 is the square foot of 8, so yea. C: I could be wrong, and because wingz proved your explanation to be correct, I'm probably wrong, but just want to know why it is 64^2 than 24^2 c:
And @tobias Eaton. It's okie, I know you tried. This is a easy question for the first part, but I made the same mistake as you did ouo.

frickity frack you are correct my friend
I missed that on my tiny screen I am very sorry it should be 24
the work through math is correct just plug in 24 otl

Eheheh. . .yeah you're right I screwed up. cx We all seem to be screwing up this particular problem for some reason. It should be 24^2 and not 64^2. Good on you to check our work and not just take our word for it, though!

I'd also like to add to what wingz said about units. Always always always remember those or your math teacher will hunt you down with a sledgehammer.

[Waki]

Thank-you all for your help! And yea, I realized my mistake ouo yep. But I have a question, shouldn't it be
8^2+24^2=c^2
Rather than
8^2+64^2=c^2?

I mean 64 is the square foot of 8, so yea. C: I could be wrong, and because wingz proved your explanation to be correct, I'm probably wrong, but just want to know why it is 64^2 than 24^2 c:
And @tobias Eaton. It's okie, I know you tried. This is a easy question for the first part, but I made the same mistake as you did ouo.

frickity frack you are correct my friend
I missed that on my tiny screen I am very sorry it should be 24
the work through math is correct just plug in 24 otl

Eheheh. . .yeah you're right I screwed up. cx We all seem to be screwing up this particular problem for some reason. It should be 24^2 and not 64^2. Good on you to check our work and not just take our word for it, though!

I'd also like to add to what wingz said about units. Always always always remember those or your math teacher will hunt you down with a sledgehammer.

Yep. She's right bobkitty lol! They will hunt you down with a sledgehammer AND a screwdriver...(hey! I find screwdrivers pretty scary K? >:c)