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[Light Bringer]

I HAVE A QUESTION!
TYPE OF QUESTION:Mathematics (Linear equations)
YOUR QUESTION:Linda thinks if a two-digit number. The sum of the digits is 8. If she reverses the digits, the new number is 36 greater than her original number. What was Linda's original number?

[Piefan]

I HAVE A QUESTION!
TYPE OF QUESTION:Mathematics (Linear equations)
YOUR QUESTION:Linda thinks if a two-digit number. The sum of the digits is 8. If she reverses the digits, the new number is 36 greater than her original number. What was Linda's original number?

Let the first digit (in the tens place) be x and the second (in the ones place) be y. For example, if she were thinking of 85, x would be 8 and y would be 5. From the question, we know that:

x + y = 8

The original number would be equal to 10x + y. The second number would be 10y + x. Therefore, we also know that

10y + x - (10x + y) = 36

Simplify it:
10y + x - 10x - y = 36
9y - 9x = 36

From there, just solve the two bolded equations simultaneously. :) Just so you can check, her original number will be 26.

[Light Bringer]

I HAVE A QUESTION!
TYPE OF QUESTION:Mathematics (Linear equations)
YOUR QUESTION:Linda thinks if a two-digit number. The sum of the digits is 8. If she reverses the digits, the new number is 36 greater than her original number. What was Linda's original number?

Let the first digit (in the tens place) be x and the second (in the ones place) be y. For example, if she were thinking of 85, x would be 8 and y would be 5. From the question, we know that:

x + y = 8

The original number would be equal to 10x + y. The second number would be 10y + x. Therefore, we also know that

10y + x - (10x + y) = 36

Simplify it:
10y + x - 10x - y = 36
9y - 9x = 36

From there, just solve the two bolded equations simultaneously. Just so you can check, her original number will be 26.

Thank you so much. I get it now.

[Kaminarii]

Mark

[Light Bringer]

I HAVE A QUESTION!
TYPE OF QUESTION:Mathematics (Linear equations)
YOUR QUESTION:Yes, I'm back. I have the answer and solution but I just don't get the working out for this one.

Make r the subject of the equation.

[kuzya]

I HAVE A QUESTION!
TYPE OF QUESTION:Mathematics (Linear equations)
YOUR QUESTION:Yes, I'm back. I have the answer and solution but I just don't get the working out for this one.

Make r the subject of the equation.
-snip-

its a typo, theyve forgotten to put the R there. If you just write it in as you marked it, the rest of the solution should make sense.

RV - rV - 2R = 0
RV - 2R = rV
R(V-2) = rV

r = [R(V-2)] / v


Silly mistake on their behalf lol

[Light Bringer]

^^
Thank you. I thought it didn't seem right but I assumed that I was just doing it wrong. Lol.

[Winstalgia]

I HAVE A QUESTION!
TYPE OF QUESTION: Physics
YOUR QUESTION:

Chef Susan tosses some pizza dough in the air, then catches it again at the same height. The pizza dough is in the air for 1.0s

We can ignore air resistance.
What was the dough's velocity at the moment it was tossed into the air?
Answer using a coordinate system where upward is positive.
Round the answer to two significant digits.

^ This question and all other questions I have to practice are similar. I'm supposed to be using a kinetic formula to solve it, and find target unknown. In this case, that'd be the velocity. This is the way the website explains it if you ask for help;

Let's list all the variables. Remember, upward is the positive direction.

a = =9.81 m/s squared

t = 1.0s

Δy = 0m

v = ?

v0 = ? < Target unknown

We should use the kinematic formula missing v to solve for the target unknown.

Δy = v0t + 1/2at2

_______________

We can rearrange the equation to solve for v0:
Δy - 1/2at2 = v0t

v0 = Δy - 1/2at2 (over) t

substituting the known values into the kinematic formula gives:

v0 = (0 m) -1/2 (-9.81 m/s2) (1.0s)2 (over) (1.0s)

4.9 m (over) 1.0s

The correct answer is 4.9 seconds.

I need a better explanation on how to solve this. I have the kinematic formulas and everything written down but when it comes to rearranging it and solving it, I get confused easily. The website usually explains stuff easily, but I've only gotten 1 right out of 5 questions, and that's not good. While this may seem like a good explanation to some, not me, it goes straight through my head. I need an explanation with mostly words if possible.

[LostInTheEcho]

I HAVE A QUESTION!
TYPE OF QUESTION: Physics
YOUR QUESTION:

Chef Susan tosses some pizza dough in the air, then catches it again at the same height. The pizza dough is in the air for 1.0s

We can ignore air resistance.
What was the dough's velocity at the moment it was tossed into the air?
Answer using a coordinate system where upward is positive.
Round the answer to two significant digits.

^ This question and all other questions I have to practice are similar. I'm supposed to be using a kinetic formula to solve it, and find target unknown. In this case, that'd be the velocity. This is the way the website explains it if you ask for help;

Let's list all the variables. Remember, upward is the positive direction.

a = =9.81 m/s squared

t = 1.0s

Δy = 0m

v = ?

v0 = ? < Target unknown

We should use the kinematic formula missing v to solve for the target unknown.

Δy = v0t + 1/2at2

_______________

We can rearrange the equation to solve for v0:
Δy - 1/2at2 = v0t

v0 = Δy - 1/2at2 (over) t

substituting the known values into the kinematic formula gives:

v0 = (0 m) -1/2 (-9.81 m/s2) (1.0s)2 (over) (1.0s)

4.9 m (over) 1.0s

The correct answer is 4.9 seconds.

I need a better explanation on how to solve this. I have the kinematic formulas and everything written down but when it comes to rearranging it and solving it, I get confused easily. The website usually explains stuff easily, but I've only gotten 1 right out of 5 questions, and that's not good. While this may seem like a good explanation to some, not me, it goes straight through my head. I need an explanation with mostly words if possible.

Okay, I hope this might help some. I'm not great at writing explainations in words but hopefully it might make things a little easier. I tried to explain each step in the rearranging of the equation so it'd be easy to follow. If you'd need something specific explained better let me know and I'll write more down for you.

[Winstalgia]

-snip-[/center]

Okay, I hope this might help some. I'm not great at writing explainations in words but hopefully it might make things a little easier. I tried to explain each step in the rearranging of the equation so it'd be easy to follow. If you'd need something specific explained better let me know and I'll write more down for you.

aa, thank you! It actually did help somewhat. I'm currently not able to review it as thoroughly as I'd like but I'll be sure to in a little. But it is helpful so thank you! I wish the website explanations had pictures/drawings or paragraphs to explain it, I did great at graphs. but thanks again! <3