Flurries wrote:Lee, wrote:Flurries wrote:-snip-
I was on the other side, thanks guys! Is this fair now? Thank you~My (so fridgnin long) calculations are;
There are 18 uncommon bunnies. 10 '15 Bunnies, 1 '13 bunny, 3 '14 bunnies, 1 '12 bunny, 1 '11 bunny and 2 '10 bunnies.
There are 8 '15 rare bunnies.
There are roughly 18 '15 common bunnies.
There is one '10 rare bunny.
8 '15 rares = 4 '14 rares = 2 '13 rares = 1 '12 rare.
10 '15 uncommon bunnies = (around) 8 '14 uncommon bunnies.
8 '14 uncommon bunnies = 4 '13 uncommon = 2 '12 uncommon = 1 '11 uncommon.
3 '14 uncommon bunnies + '13 uncommon bunny = 2 '13 uncommon bunnies = 1 '12 uncommon + 1 '12 uncommon = '11 uncommon + '11 uncommon = '10 uncommon.
2 '10 bunnies = '11 rare.
18 '15 commons = 4 '14 uncommons = '2 ;13 uncommons = 1 '12 uncommon.
'11 uncommon + '10 uncommon + '11 rare + '12 uncommon + '10 rare + '12 rare = Underpay for 1 '09 rare atleast. ^^
Some I didn't even understand ;_; So I'm guessing it's unfair to me (The '09 rares)? Thank you ^^
'11 uncommon + '10 uncommon + '11 rare + '12 uncommon + '10 rare + '12 rare = Underpay for 1 '09 rare atleast. ^^
The answer was at the bottom. ^^
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